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Gravity and Free Fall

Manual: General · Subject: Mechanics

Investigate gravitational acceleration, free-fall motion, terminal velocity due to air resistance, and the independence of horizontal and vertical motion in projectile problems.

Section

Gravitational Acceleration and Weight

Near Earth's surface, all objects experience a downward gravitational acceleration of:<br>g=9.81 m/s2g = 9.81\ \text{m/s}^2

This value is essentially constant close to the surface (it decreases slightly at higher altitudes). Weight is the gravitational force exerted on an object:<br>W=mgW = mg<br>where WW is weight (N), mm is mass (kg), and g=9.81 m/s2g = 9.81\ \text{m/s}^2.

Example: A person of mass 65 kg has a weight of W=65×9.81=637.65 NW = 65 \times 9.81 = 637.65\ \text{N} on Earth's surface.

Important distinction: Mass is the amount of matter in an object (kg) — it is the same everywhere. Weight is a force that depends on gravitational field strength (N) — it varies by location. An astronaut on the Moon weighs about one-sixth of their Earth weight, but their mass is unchanged.

Free Fall

An object in free fall is subject only to gravity — air resistance is neglected. In free fall, every object accelerates downward at g=9.81 m/s2g = 9.81\ \text{m/s}^2, regardless of its mass. This was Galileo's great insight, confirmed centuries later in vacuum experiments.

Key free-fall equations (object starting from rest, taking downward as positive):<br>v=gtv = gt<br>h=12gt2h = \frac{1}{2}gt^2<br>v2=2ghv^2 = 2gh

Example: An object is dropped from rest. After 3 s:

  • Speed: v=9.81×3=29.43 m/sv = 9.81 \times 3 = 29.43\ \text{m/s}
  • Distance fallen: h=12×9.81×32=44.1 mh = \frac{1}{2} \times 9.81 \times 3^2 = 44.1\ \text{m}
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Terminal velocity occurs when air resistance equals the gravitational force on a falling object. At that point net force = 0, so acceleration = 0 and the object falls at constant speed. A skydiver in free fall reaches terminal velocity of about 55 m/s55\ \text{m/s} (≈ 200 km/h). Deploying a parachute greatly increases air resistance, reducing terminal velocity to a safe landing speed of roughly 5 m/s5\ \text{m/s}.

Projectile Motion

A projectile is an object launched into the air subject only to gravity (air resistance neglected). The key principle is the independence of horizontal and vertical motion:

  • Horizontal: No net horizontal force acts on the projectile, so horizontal velocity vxv_x remains constant. Horizontal distance: x=vxtx = v_x t.
  • Vertical: Gravity causes a constant downward acceleration gg, described by the same free-fall equations.

Example: A ball is thrown horizontally from a cliff at 10 m/s10\ \text{m/s} and takes 2 s to reach the ground.

  • Horizontal distance: x=10×2=20 mx = 10 \times 2 = 20\ \text{m}
  • Vertical drop: h=12×9.81×22=19.6 mh = \frac{1}{2} \times 9.81 \times 2^2 = 19.6\ \text{m}

A key consequence: a ball thrown horizontally and a ball simply dropped from the same height will hit the ground at exactly the same time, because their vertical motions are identical.

Multiple choice question

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Short answer question

Short answer question