← Back to CoursesEinstein & Relativity: Advanced

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Relativistic Dynamics and Conservation Laws

Manual: General · Subject: Physics

Derives relativistic momentum, energy, mass-energy equivalence, and conservation-law structure.

Energy, Momentum, and Mass

Relativistic Momentum

The relativistic three-momentum is p=γmv.\mathbf{p} = \gamma m\mathbf{v}. This reduces to Newtonian momentum mvm\mathbf{v} when v≪cv \ll c but differs strongly at high speed because γ\gamma grows rapidly.

Relativistic Energy

The total energy is E=γmc2,E = \gamma mc^2, and the kinetic energy is K=(γ−1)mc2.K = (\gamma - 1)mc^2. The energy-momentum relation is E2=p2c2+m2c4.E^2 = p^2c^2 + m^2c^4.

Mass-Energy Equivalence

Einstein’s relation E0=mc2E_0 = mc^2 identifies rest energy as an intrinsic property of matter. It implies that rest mass is a measure of internal energy content, not simply a mechanical bookkeeping parameter.

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Important Distinction

Modern treatments usually reserve mm for invariant rest mass and avoid the obsolete notion of velocity-dependent relativistic mass.

Which relation is correct for a free massive particle?

What is the kinetic energy of a particle in special relativity?

Dynamics Formulas

QuantityExpressionLow-Speed Limit
Momentump=γmv\mathbf{p} = \gamma m\mathbf{v}mvm\mathbf{v}
Total energyE=γmc2E = \gamma mc^2mc2+12mv2mc^2 + \frac{1}{2}mv^2
Kinetic energyK=(γ−1)mc2K = (\gamma-1)mc^212mv2\frac{1}{2}mv^2
Invariant relationE2=p2c2+m2c4E^2 = p^2c^2 + m^2c^4E≈mc2E \approx mc^2 for small pp

Why does a massive particle’s speed never reach cc under finite energy input?

Conservation-Law Procedure

  1. 1

    Step 1: Write energy and momentum in four-vector form.

  2. 2

    Step 2: Use symmetry or interaction assumptions to define conserved quantities.

  3. 3

    Step 3: Apply the invariant mass-shell relation.

  4. 4

    Step 4: Take the nonrelativistic limit to verify consistency with classical mechanics.