Quantum Field Theory I: Free Fields, Propagators, and Interactions
Why quantum field theory?
Fields as operator-valued distributions
In quantum field theory, the field itself is promoted to an operator-valued distribution acting on a Fock space. Particle number can change, so a single-particle quantum mechanics description is insufficient for relativistic interacting systems. QFT is the framework that combines quantum mechanics, special relativity, and locality.
Core insight
Interactions are most efficiently organized by the field content, symmetry, and power counting of the Lagrangian density.
Free scalar, fermion, and gauge fields
Propagators
The free scalar propagator is the inverse of the Klein-Gordon operator and in momentum space is proportional to . Similar structures exist for fermions and gauge bosons, with gauge fixing required to define the inverse kinetic operator for gauge fields.
Interactions and vertices
Perturbation theory is organized by interaction terms such as , Yukawa couplings, or gauge couplings. Feynman rules translate the Lagrangian into diagrammatic contributions, with external legs, propagators, and vertices systematically encoding amplitudes.
What does a propagator represent in perturbative QFT?
The propagator is the Green's function of the free theory and describes how excitations propagate between spacetime points.
Correct answer: An inverse kinetic operator or amplitude for field propagation
Why is gauge fixing needed in gauge-field quantization?
Gauge invariance creates equivalent configurations; gauge fixing selects representatives and allows construction of propagators.
Correct answer: Because the kinetic operator is not invertible before removing gauge redundancy
Perturbative amplitudes
Diagrammatic expansion
Scattering amplitudes are computed as expansions in the coupling constant. Each connected diagram contributes a specific momentum integral and symmetry factor. Renormalizable theories are those whose ultraviolet divergences can be absorbed into a finite number of parameters of the original Lagrangian.
What is the function of gauge fixing in the path integral?
Gauge fixing resolves the overcounting due to gauge redundancy and makes the functional integral well-defined.
Correct answer: To remove redundant gauge-equivalent configurations
What does renormalizability mean at the perturbative level?
This ensures predictive power despite divergent intermediate quantities.
Correct answer: That ultraviolet divergences can be absorbed into a finite set of parameters/counterterms