Mathematical Foundations of Quantum Mechanics
Why the formalism matters
State vectors and complex vector spaces
Quantum states live in a complex Hilbert space , where vectors are defined up to an overall phase. Physical predictions depend on inner products, norms, and linear maps, not on a chosen coordinate representation.
Core principle
A quantum theory is specified not just by states, but by the algebra of observables, symmetry actions, and the rule assigning probabilities to measurement outcomes.
Common mathematical objects
| Object | Role |
|---|---|
| Hilbert space | State space with inner product |
| Hermitian operator | Observable |
| Unitary operator | Time evolution / symmetry |
| Projector | Measurement event |
Operators and spectral decomposition
For a self-adjoint operator , the spectral theorem generalizes diagonalization. In finite dimensions, ; in infinite dimensions, the spectral measure replaces a simple eigenbasis.
Which property is essential for an operator to represent an observable in standard quantum mechanics?
Observables are represented by self-adjoint operators so that measurement outcomes are real and the spectral theorem applies.
Correct answer: It must be self-adjoint on the Hilbert space
Bra-ket notation and dual spaces
If , then the dual vector acts linearly on kets, giving amplitudes . The norm is and probabilities follow the Born rule.
What is the physical significance of the global phase of a quantum state?
States that differ by an overall phase represent the same physical ray in Hilbert space.
Correct answer: It has no physical significance
Rigged Hilbert spaces and distributions
Continuous spectra
Momentum and position eigenstates are not normalizable in the usual Hilbert-space sense. They are handled rigorously using a rigged Hilbert space or Gelfand triple, where generalized eigenvectors act as distributions.
Why are plane-wave momentum eigenstates not square-integrable?
A plane wave extends over all space with constant amplitude, so its integral norm diverges.
Correct answer: Their modulus does not decay at infinity
The position operator on has what kind of spectrum?
Position on the real line has continuous spectrum, with generalized eigenvectors .
Correct answer: Continuous
Study tip
For advanced quantum mechanics, practice moving between abstract operator statements and explicit coordinate representations; both are used heavily in research papers.